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16140061317 = 35380020439
BaseRepresentation
bin11110000100000010…
…11100101010000101
31112122211101001210210
433002001130222011
5231023323430232
611225321310033
71110652154232
oct170201345205
945584331723
1016140061317
116932709a56
123165335319
1316a2ab5453
14ad17d0789
15646e605cc
hex3c205ca85

16140061317 has 4 divisors (see below), whose sum is σ = 21520081760. Its totient is φ = 10760040876.

The previous prime is 16140061277. The next prime is 16140061337. The reversal of 16140061317 is 71316004161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 71316004161 = 323772001387.

It is not a de Polignac number, because 16140061317 - 212 = 16140057221 is a prime.

It is a super-3 number, since 3×161400613173 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16140061337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2690010217 + ... + 2690010222.

It is an arithmetic number, because the mean of its divisors is an integer number (5380020440).

Almost surely, 216140061317 is an apocalyptic number.

It is an amenable number.

16140061317 is a deficient number, since it is larger than the sum of its proper divisors (5380020443).

16140061317 is an equidigital number, since it uses as much as digits as its factorization.

16140061317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5380020442.

The product of its (nonzero) digits is 3024, while the sum is 30.

Adding to 16140061317 its reverse (71316004161), we get a palindrome (87456065478).

The spelling of 16140061317 in words is "sixteen billion, one hundred forty million, sixty-one thousand, three hundred seventeen".

Divisors: 1 3 5380020439 16140061317