Base | Representation |
---|---|
bin | 1110101011100111101110… |
… | …0111100110000100110011 |
3 | 2010011012202211120210121012 |
4 | 3222321323213212010303 |
5 | 4103434431113404012 |
6 | 54155442402421135 |
7 | 3254155466120306 |
oct | 352717347460463 |
9 | 63135684523535 |
10 | 16142561075507 |
11 | 5164026989539 |
12 | 19886530617ab |
13 | 9013108420a9 |
14 | 3db438738b3d |
15 | 1ced8988e622 |
hex | eae7b9e6133 |
16142561075507 has 2 divisors, whose sum is σ = 16142561075508. Its totient is φ = 16142561075506.
The previous prime is 16142561075503. The next prime is 16142561075573. The reversal of 16142561075507 is 70557016524161.
It is a weak prime.
It is an emirp because it is prime and its reverse (70557016524161) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16142561075507 - 22 = 16142561075503 is a prime.
It is not a weakly prime, because it can be changed into another prime (16142561075503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8071280537753 + 8071280537754.
It is an arithmetic number, because the mean of its divisors is an integer number (8071280537754).
Almost surely, 216142561075507 is an apocalyptic number.
16142561075507 is a deficient number, since it is larger than the sum of its proper divisors (1).
16142561075507 is an equidigital number, since it uses as much as digits as its factorization.
16142561075507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1764000, while the sum is 50.
Adding to 16142561075507 its reverse (70557016524161), we get a palindrome (86699577599668).
The spelling of 16142561075507 in words is "sixteen trillion, one hundred forty-two billion, five hundred sixty-one million, seventy-five thousand, five hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •