Base | Representation |
---|---|
bin | 1001011001011000110… |
… | …1101101001100100011 |
3 | 120102200121111010122121 |
4 | 2112112031231030203 |
5 | 10121104043342342 |
6 | 202054534045111 |
7 | 14443325031124 |
oct | 2262615551443 |
9 | 512617433577 |
10 | 161433965347 |
11 | 625112a0596 |
12 | 27353aa9797 |
13 | 122b937b225 |
14 | 7b5614804b |
15 | 42ec7e1067 |
hex | 259636d323 |
161433965347 has 2 divisors, whose sum is σ = 161433965348. Its totient is φ = 161433965346.
The previous prime is 161433965327. The next prime is 161433965377. The reversal of 161433965347 is 743569334161.
161433965347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161433965347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 161433965294 and 161433965303.
It is not a weakly prime, because it can be changed into another prime (161433965327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80716982673 + 80716982674.
It is an arithmetic number, because the mean of its divisors is an integer number (80716982674).
Almost surely, 2161433965347 is an apocalyptic number.
161433965347 is a deficient number, since it is larger than the sum of its proper divisors (1).
161433965347 is an equidigital number, since it uses as much as digits as its factorization.
161433965347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4898880, while the sum is 52.
The spelling of 161433965347 in words is "one hundred sixty-one billion, four hundred thirty-three million, nine hundred sixty-five thousand, three hundred forty-seven".
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