161450005541337 has 48 divisors (see below), whose sum is σ = 253086156056448. Its totient is φ = 98910841962240.

The previous prime is 161450005541317. The next prime is 161450005541351. The reversal of 161450005541337 is 733145500054161.

161450005541337 is a `hidden beast` number, since 1 + 6 + 1 + 4 + 50 + 0 + 0 + 554 + 13 + 37 = 666.

It is not a de Polignac number, because 161450005541337 - 2⁸ = 161450005541081 is a prime.

It is a super-2 number, since 2×161450005541337² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 161450005541292 and 161450005541301.

It is not an unprimeable number, because it can be changed into a prime (161450005541317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 148132548 + ... + 149218469.

It is an arithmetic number, because the mean of its divisors is an integer number (5272628251176).

Almost surely, 2^{161450005541337} is an apocalyptic number.

It is an amenable number.

161450005541337 is a deficient number, since it is larger than the sum of its proper divisors (91636150515111).

161450005541337 is a wasteful number, since it uses less digits than its factorization.

161450005541337 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297351150 (or 297351147 counting only the distinct ones).

The product of its (nonzero) digits is 756000, while the sum is 45.

Adding to 161450005541337 its reverse (733145500054161), we get a palindrome (894595505595498).

The spelling of 161450005541337 in words is "one hundred sixty-one trillion, four hundred fifty billion, five million, five hundred forty-one thousand, three hundred thirty-seven".