Base | Representation |
---|---|
bin | 1001011001011111010… |
… | …1011011010111111011 |
3 | 120102202111122112021202 |
4 | 2112113311123113323 |
5 | 10121133023432243 |
6 | 202101344524415 |
7 | 14444105114156 |
oct | 2262765332773 |
9 | 512674575252 |
10 | 161461155323 |
11 | 62525681846 |
12 | 2736102070b |
13 | 122c1bab180 |
14 | 7b599c4c9d |
15 | 42eedb24b8 |
hex | 2597d5b5fb |
161461155323 has 32 divisors (see below), whose sum is σ = 185641243200. Its totient is φ = 139109068800.
The previous prime is 161461155307. The next prime is 161461155341. The reversal of 161461155323 is 323551164161.
It is not a de Polignac number, because 161461155323 - 24 = 161461155307 is a prime.
It is a super-3 number, since 3×1614611553233 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (161461155343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39388328 + ... + 39392426.
It is an arithmetic number, because the mean of its divisors is an integer number (5801288850).
Almost surely, 2161461155323 is an apocalyptic number.
161461155323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
161461155323 is a deficient number, since it is larger than the sum of its proper divisors (24180087877).
161461155323 is a wasteful number, since it uses less digits than its factorization.
161461155323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5567.
The product of its digits is 64800, while the sum is 38.
The spelling of 161461155323 in words is "one hundred sixty-one billion, four hundred sixty-one million, one hundred fifty-five thousand, three hundred twenty-three".
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