Base | Representation |
---|---|
bin | 100100101111110000000100… |
… | …010011001111010001100011 |
3 | 210012012212111112112111220012 |
4 | 210233300010103033101203 |
5 | 132140314014000103201 |
6 | 1331415040511035135 |
7 | 46020005516504564 |
oct | 4457600423172143 |
9 | 705185445474805 |
10 | 161611101566051 |
11 | 47548979706645 |
12 | 16161392b0baab |
13 | 6c23b278b6357 |
14 | 2bca03a3c416b |
15 | 13a3d203a95bb |
hex | 92fc044cf463 |
161611101566051 has 2 divisors, whose sum is σ = 161611101566052. Its totient is φ = 161611101566050.
The previous prime is 161611101566011. The next prime is 161611101566087. The reversal of 161611101566051 is 150665101116161.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161611101566051 is a prime.
It is a super-2 number, since 2×1616111015660512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (161611101566011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80805550783025 + 80805550783026.
It is an arithmetic number, because the mean of its divisors is an integer number (80805550783026).
Almost surely, 2161611101566051 is an apocalyptic number.
161611101566051 is a deficient number, since it is larger than the sum of its proper divisors (1).
161611101566051 is an equidigital number, since it uses as much as digits as its factorization.
161611101566051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 41.
The spelling of 161611101566051 in words is "one hundred sixty-one trillion, six hundred eleven billion, one hundred one million, five hundred sixty-six thousand, fifty-one".
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