Base | Representation |
---|---|
bin | 100100101111110000000100… |
… | …010011100011110010100011 |
3 | 210012012212111112200210011111 |
4 | 210233300010103203302203 |
5 | 132140314014010300313 |
6 | 1331415040512524151 |
7 | 46020005520304561 |
oct | 4457600423436243 |
9 | 705185445623144 |
10 | 161611101650083 |
11 | 47548979763798 |
12 | 16161392b50657 |
13 | 6c23b27915687 |
14 | 2bca03a406a31 |
15 | 13a3d203c443d |
hex | 92fc044e3ca3 |
161611101650083 has 2 divisors, whose sum is σ = 161611101650084. Its totient is φ = 161611101650082.
The previous prime is 161611101649993. The next prime is 161611101650101. The reversal of 161611101650083 is 380056101116161.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-161611101650083 is a prime.
It is a super-2 number, since 2×1616111016500832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (161611101650783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80805550825041 + 80805550825042.
It is an arithmetic number, because the mean of its divisors is an integer number (80805550825042).
Almost surely, 2161611101650083 is an apocalyptic number.
161611101650083 is a deficient number, since it is larger than the sum of its proper divisors (1).
161611101650083 is an equidigital number, since it uses as much as digits as its factorization.
161611101650083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 40.
The spelling of 161611101650083 in words is "one hundred sixty-one trillion, six hundred eleven billion, one hundred one million, six hundred fifty thousand, eighty-three".
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