Base | Representation |
---|---|
bin | 111101110001… |
… | …101000111011 |
3 | 1010110202010202 |
4 | 331301220323 |
5 | 13121202412 |
6 | 1335032415 |
7 | 254435066 |
oct | 75615073 |
9 | 33422122 |
10 | 16194107 |
11 | 9160966 |
12 | 550b70b |
13 | 3480017 |
14 | 22178dd |
15 | 164d3c2 |
hex | f71a3b |
16194107 has 2 divisors, whose sum is σ = 16194108. Its totient is φ = 16194106.
The previous prime is 16194103. The next prime is 16194119. The reversal of 16194107 is 70149161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16194107 - 22 = 16194103 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16194107.
It is not a weakly prime, because it can be changed into another prime (16194103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8097053 + 8097054.
It is an arithmetic number, because the mean of its divisors is an integer number (8097054).
Almost surely, 216194107 is an apocalyptic number.
16194107 is a deficient number, since it is larger than the sum of its proper divisors (1).
16194107 is an equidigital number, since it uses as much as digits as its factorization.
16194107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 29.
The square root of 16194107 is about 4024.1902291020. The cubic root of 16194107 is about 252.9991147047. Note that the first 3 decimals are identical.
The spelling of 16194107 in words is "sixteen million, one hundred ninety-four thousand, one hundred seven".
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