162023131 has 2 divisors, whose sum is σ = 162023132. Its totient is φ = 162023130.

The previous prime is 162023101. The next prime is 162023167. The reversal of 162023131 is 131320261.

162023131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (131320261) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-162023131 is a prime.

It is a super-2 number, since 2×162023131² = 52502989958086322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 162023099 and 162023108.

It is not a weakly prime, because it can be changed into another prime (162023101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81011565 + 81011566.

It is an arithmetic number, because the mean of its divisors is an integer number (81011566).

Almost surely, 2^162023131 is an apocalyptic number.

162023131 is a deficient number, since it is larger than the sum of its proper divisors (1).

162023131 is an equidigital number, since it uses as much as digits as its factorization.

162023131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 162023131 is about 12728.8307004218. The cubic root of 162023131 is about 545.1621221806.

Adding to 162023131 its reverse (131320261), we get a palindrome (293343392).

The spelling of 162023131 in words is "one hundred sixty-two million, twenty-three thousand, one hundred thirty-one".