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16203113 is a prime number
BaseRepresentation
bin111101110011…
…110101101001
31010111012111022
4331303311221
513121444423
61335142225
7254503253
oct75636551
933435438
1016203113
119167703
125514975
133484154
14221acd3
151650dc8
hexf73d69

16203113 has 2 divisors, whose sum is σ = 16203114. Its totient is φ = 16203112.

The previous prime is 16203101. The next prime is 16203157. The reversal of 16203113 is 31130261.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13601344 + 2601769 = 3688^2 + 1613^2 .

It is an emirp because it is prime and its reverse (31130261) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16203113 - 210 = 16202089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16203091 and 16203100.

It is not a weakly prime, because it can be changed into another prime (16203163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8101556 + 8101557.

It is an arithmetic number, because the mean of its divisors is an integer number (8101557).

Almost surely, 216203113 is an apocalyptic number.

It is an amenable number.

16203113 is a deficient number, since it is larger than the sum of its proper divisors (1).

16203113 is an equidigital number, since it uses as much as digits as its factorization.

16203113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 16203113 is about 4025.3090564577. The cubic root of 16203113 is about 253.0460059962.

Adding to 16203113 its reverse (31130261), we get a palindrome (47333374).

The spelling of 16203113 in words is "sixteen million, two hundred three thousand, one hundred thirteen".