Base | Representation |
---|---|
bin | 100100111010000100011010… |
… | …000001011101111011110111 |
3 | 210021201122122100011220022021 |
4 | 210322010122001131323313 |
5 | 132233423114204010403 |
6 | 1333120501343214011 |
7 | 46122146164443142 |
oct | 4472043201357367 |
9 | 707648570156267 |
10 | 162320135610103 |
11 | 477a1645969249 |
12 | 16256890ba7307 |
13 | 6c75952893193 |
14 | 2c1249d443059 |
15 | 13b74bc6158bd |
hex | 93a11a05def7 |
162320135610103 has 4 divisors (see below), whose sum is σ = 162320556276360. Its totient is φ = 162319714943848.
The previous prime is 162320135610041. The next prime is 162320135610151. The reversal of 162320135610103 is 301016531023261.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-162320135610103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (162320135611103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209753800 + ... + 210526237.
It is an arithmetic number, because the mean of its divisors is an integer number (40580139069090).
Almost surely, 2162320135610103 is an apocalyptic number.
162320135610103 is a deficient number, since it is larger than the sum of its proper divisors (420666257).
162320135610103 is an equidigital number, since it uses as much as digits as its factorization.
162320135610103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 420666256.
The product of its (nonzero) digits is 19440, while the sum is 34.
Adding to 162320135610103 its reverse (301016531023261), we get a palindrome (463336666633364).
The spelling of 162320135610103 in words is "one hundred sixty-two trillion, three hundred twenty billion, one hundred thirty-five million, six hundred ten thousand, one hundred three".
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