Base | Representation |
---|---|
bin | 1001011100110110010… |
… | …1101111100000001011 |
3 | 120112002100122122121210 |
4 | 2113031211233200023 |
5 | 10130004412410011 |
6 | 202331042504203 |
7 | 14505335561214 |
oct | 2271545574013 |
9 | 515070578553 |
10 | 162363013131 |
11 | 62948762980 |
12 | 27573065063 |
13 | 124069a5347 |
14 | 7c036a640b |
15 | 43541596a6 |
hex | 25cd96f80b |
162363013131 has 32 divisors (see below), whose sum is σ = 241996398336. Its totient is φ = 95973248000.
The previous prime is 162363013103. The next prime is 162363013147. The reversal of 162363013131 is 131310363261.
It is a cyclic number.
It is not a de Polignac number, because 162363013131 - 26 = 162363013067 is a prime.
It is a super-2 number, since 2×1623630131312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (162363013151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5072680 + ... + 5104586.
It is an arithmetic number, because the mean of its divisors is an integer number (7562387448).
Almost surely, 2162363013131 is an apocalyptic number.
162363013131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
162363013131 is a deficient number, since it is larger than the sum of its proper divisors (79633385205).
162363013131 is a wasteful number, since it uses less digits than its factorization.
162363013131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35723.
The product of its (nonzero) digits is 5832, while the sum is 30.
Adding to 162363013131 its reverse (131310363261), we get a palindrome (293673376392).
The spelling of 162363013131 in words is "one hundred sixty-two billion, three hundred sixty-three million, thirteen thousand, one hundred thirty-one".
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