Search a number
-
+
162600425137 is a prime number
BaseRepresentation
bin1001011101101110111…
…1011001011010110001
3120112200220101102200001
42113123233121122301
510131001202101022
6202410403230001
714514250544413
oct2273357313261
9515626342601
10162600425137
1162a5a779047
122761a678301
1312443c2b217
147c270269b3
154369e03b27
hex25dbbd96b1

162600425137 has 2 divisors, whose sum is σ = 162600425138. Its totient is φ = 162600425136.

The previous prime is 162600425083. The next prime is 162600425167. The reversal of 162600425137 is 731524006261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 161354052721 + 1246372416 = 401689^2 + 35304^2 .

It is a cyclic number.

It is not a de Polignac number, because 162600425137 - 231 = 160452941489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 162600425096 and 162600425105.

It is not a weakly prime, because it can be changed into another prime (162600425167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81300212568 + 81300212569.

It is an arithmetic number, because the mean of its divisors is an integer number (81300212569).

Almost surely, 2162600425137 is an apocalyptic number.

It is an amenable number.

162600425137 is a deficient number, since it is larger than the sum of its proper divisors (1).

162600425137 is an equidigital number, since it uses as much as digits as its factorization.

162600425137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 37.

The spelling of 162600425137 in words is "one hundred sixty-two billion, six hundred million, four hundred twenty-five thousand, one hundred thirty-seven".