Search a number
-
+
1626813174113 is a prime number
BaseRepresentation
bin10111101011000101100…
…111110001000101100001
312202112002101222212001222
4113223011213301011201
5203123203133032423
63243203032104425
7225350642552231
oct27530547610541
95675071885058
101626813174113
11577a22698016
12223354535115
13ba53bcb2b3a
1458a497b9cc1
152c4b55633c8
hex17ac59f1161

1626813174113 has 2 divisors, whose sum is σ = 1626813174114. Its totient is φ = 1626813174112.

The previous prime is 1626813174067. The next prime is 1626813174131. The reversal of 1626813174113 is 3114713186261.

Together with next prime (1626813174131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1266203316049 + 360609858064 = 1125257^2 + 600508^2 .

It is a cyclic number.

It is not a de Polignac number, because 1626813174113 - 216 = 1626813108577 is a prime.

It is a super-2 number, since 2×16268131741132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1626813174143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 813406587056 + 813406587057.

It is an arithmetic number, because the mean of its divisors is an integer number (813406587057).

Almost surely, 21626813174113 is an apocalyptic number.

It is an amenable number.

1626813174113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1626813174113 is an equidigital number, since it uses as much as digits as its factorization.

1626813174113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145152, while the sum is 44.

The spelling of 1626813174113 in words is "one trillion, six hundred twenty-six billion, eight hundred thirteen million, one hundred seventy-four thousand, one hundred thirteen".