Base | Representation |
---|---|
bin | 11110010110010011… |
… | …10101001111000011 |
3 | 1120001111122001202221 |
4 | 33023021311033003 |
5 | 231332033112313 |
6 | 11252432551511 |
7 | 1114522242331 |
oct | 171311651703 |
9 | 46044561687 |
10 | 16293254083 |
11 | 6a01131a47 |
12 | 31a86b2597 |
13 | 16c8761662 |
14 | b07caab51 |
15 | 655620c8d |
hex | 3cb2753c3 |
16293254083 has 2 divisors, whose sum is σ = 16293254084. Its totient is φ = 16293254082.
The previous prime is 16293254077. The next prime is 16293254137. The reversal of 16293254083 is 38045239261.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16293254083 - 25 = 16293254051 is a prime.
It is a super-2 number, since 2×162932540832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16293254183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8146627041 + 8146627042.
It is an arithmetic number, because the mean of its divisors is an integer number (8146627042).
Almost surely, 216293254083 is an apocalyptic number.
16293254083 is a deficient number, since it is larger than the sum of its proper divisors (1).
16293254083 is an equidigital number, since it uses as much as digits as its factorization.
16293254083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 16293254083 in words is "sixteen billion, two hundred ninety-three million, two hundred fifty-four thousand, eighty-three".
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