Base | Representation |
---|---|
bin | 10111101110000011101… |
… | …000100100010111110001 |
3 | 12202211022120112222211111 |
4 | 113232003220210113301 |
5 | 203201220232231332 |
6 | 3244451231313321 |
7 | 225522642236233 |
oct | 27560350442761 |
9 | 5684276488744 |
10 | 1630001055217 |
11 | 5793091132a7 |
12 | 223aa407b841 |
13 | ba92959a512 |
14 | 58c6cd2c253 |
15 | 2c60036a947 |
hex | 17b83a245f1 |
1630001055217 has 2 divisors, whose sum is σ = 1630001055218. Its totient is φ = 1630001055216.
The previous prime is 1630001055157. The next prime is 1630001055271. The reversal of 1630001055217 is 7125501000361.
Together with next prime (1630001055271) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1614891974656 + 15109080561 = 1270784^2 + 122919^2 .
It is a cyclic number.
It is not a de Polignac number, because 1630001055217 - 223 = 1629992666609 is a prime.
It is not a weakly prime, because it can be changed into another prime (1630001053217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 815000527608 + 815000527609.
It is an arithmetic number, because the mean of its divisors is an integer number (815000527609).
Almost surely, 21630001055217 is an apocalyptic number.
It is an amenable number.
1630001055217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1630001055217 is an equidigital number, since it uses as much as digits as its factorization.
1630001055217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 1630001055217 its reverse (7125501000361), we get a palindrome (8755502055578).
The spelling of 1630001055217 in words is "one trillion, six hundred thirty billion, one million, fifty-five thousand, two hundred seventeen".
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