Base | Representation |
---|---|
bin | 1110110101001010100110… |
… | …1010101101111001001011 |
3 | 2010201220000222101100101101 |
4 | 3231102221222231321023 |
5 | 4114131244323400042 |
6 | 54403042215402231 |
7 | 3302052215320603 |
oct | 355225152557113 |
9 | 63656028340341 |
10 | 16306542403147 |
11 | 5217625092017 |
12 | 19b4398083377 |
13 | 913914893389 |
14 | 405352d01c03 |
15 | 1d4285b146b7 |
hex | ed4a9aade4b |
16306542403147 has 2 divisors, whose sum is σ = 16306542403148. Its totient is φ = 16306542403146.
The previous prime is 16306542403141. The next prime is 16306542403181. The reversal of 16306542403147 is 74130424560361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16306542403147 - 223 = 16306534014539 is a prime.
It is a super-2 number, since 2×163065424031472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16306542403097 and 16306542403106.
It is not a weakly prime, because it can be changed into another prime (16306542403141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8153271201573 + 8153271201574.
It is an arithmetic number, because the mean of its divisors is an integer number (8153271201574).
Almost surely, 216306542403147 is an apocalyptic number.
16306542403147 is a deficient number, since it is larger than the sum of its proper divisors (1).
16306542403147 is an equidigital number, since it uses as much as digits as its factorization.
16306542403147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 46.
The spelling of 16306542403147 in words is "sixteen trillion, three hundred six billion, five hundred forty-two million, four hundred three thousand, one hundred forty-seven".
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