Base | Representation |
---|---|
bin | 1110110101011000000110… |
… | …1011110010110100101001 |
3 | 2010202020101112212210122012 |
4 | 3231112001223302310221 |
5 | 4114211210120023022 |
6 | 54404442002005305 |
7 | 3302241063221615 |
oct | 355260153626451 |
9 | 63666345783565 |
10 | 16310166564137 |
11 | 5219114902896 |
12 | 19b5029946835 |
13 | 914071682834 |
14 | 4055b8380345 |
15 | 1d43e8d99de2 |
hex | ed581af2d29 |
16310166564137 has 2 divisors, whose sum is σ = 16310166564138. Its totient is φ = 16310166564136.
The previous prime is 16310166564113. The next prime is 16310166564163. The reversal of 16310166564137 is 73146566101361.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11879747783401 + 4430418780736 = 3446701^2 + 2104856^2 .
It is a cyclic number.
It is not a de Polignac number, because 16310166564137 - 28 = 16310166563881 is a prime.
It is not a weakly prime, because it can be changed into another prime (16310166564037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8155083282068 + 8155083282069.
It is an arithmetic number, because the mean of its divisors is an integer number (8155083282069).
Almost surely, 216310166564137 is an apocalyptic number.
It is an amenable number.
16310166564137 is a deficient number, since it is larger than the sum of its proper divisors (1).
16310166564137 is an equidigital number, since it uses as much as digits as its factorization.
16310166564137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 50.
The spelling of 16310166564137 in words is "sixteen trillion, three hundred ten billion, one hundred sixty-six million, five hundred sixty-four thousand, one hundred thirty-seven".
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