Base | Representation |
---|---|
bin | 100101000101011101110110… |
… | …001100110100000010100011 |
3 | 210101111112022000121002102101 |
4 | 211011131312030310002203 |
5 | 132334241143212322341 |
6 | 1334520352455431231 |
7 | 46232554314200062 |
oct | 4505356614640243 |
9 | 711445260532371 |
10 | 163103366135971 |
11 | 47a738270a6908 |
12 | 16362637385517 |
13 | 7001773530ba1 |
14 | 2c3c3605761d9 |
15 | 13cca5d5b9831 |
hex | 9457763340a3 |
163103366135971 has 2 divisors, whose sum is σ = 163103366135972. Its totient is φ = 163103366135970.
The previous prime is 163103366135921. The next prime is 163103366136059. The reversal of 163103366135971 is 179531663301361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 163103366135971 - 221 = 163103364038819 is a prime.
It is a super-2 number, since 2×1631033661359712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (163103366135921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81551683067985 + 81551683067986.
It is an arithmetic number, because the mean of its divisors is an integer number (81551683067986).
Almost surely, 2163103366135971 is an apocalyptic number.
163103366135971 is a deficient number, since it is larger than the sum of its proper divisors (1).
163103366135971 is an equidigital number, since it uses as much as digits as its factorization.
163103366135971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5511240, while the sum is 55.
The spelling of 163103366135971 in words is "one hundred sixty-three trillion, one hundred three billion, three hundred sixty-six million, one hundred thirty-five thousand, nine hundred seventy-one".
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