Base | Representation |
---|---|
bin | 100101000101100000110001… |
… | …101001111111000011011011 |
3 | 210101111211102012102222002112 |
4 | 211011200301221333003123 |
5 | 132334314113321411101 |
6 | 1334522032523422535 |
7 | 46233025253142335 |
oct | 4505406151770333 |
9 | 711454365388075 |
10 | 163106511122651 |
11 | 47a750a0394958 |
12 | 16363174684a4b |
13 | 7001b54c7a455 |
14 | 2c3c57c120455 |
15 | 13ccb9474c6bb |
hex | 945831a7f0db |
163106511122651 has 2 divisors, whose sum is σ = 163106511122652. Its totient is φ = 163106511122650.
The previous prime is 163106511122623. The next prime is 163106511122663. The reversal of 163106511122651 is 156221115601361.
163106511122651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 163106511122651 - 238 = 162831633215707 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 163106511122599 and 163106511122608.
It is not a weakly prime, because it can be changed into another prime (163106511122671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81553255561325 + 81553255561326.
It is an arithmetic number, because the mean of its divisors is an integer number (81553255561326).
Almost surely, 2163106511122651 is an apocalyptic number.
163106511122651 is a deficient number, since it is larger than the sum of its proper divisors (1).
163106511122651 is an equidigital number, since it uses as much as digits as its factorization.
163106511122651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 41.
The spelling of 163106511122651 in words is "one hundred sixty-three trillion, one hundred six billion, five hundred eleven million, one hundred twenty-two thousand, six hundred fifty-one".
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