Base | Representation |
---|---|
bin | 1001011111110000101… |
… | …0010010011101011001 |
3 | 120121002210212110001012 |
4 | 2113330022102131121 |
5 | 10133104423023213 |
6 | 202540353303305 |
7 | 14533604025026 |
oct | 2277412223531 |
9 | 517083773035 |
10 | 163144345433 |
11 | 63209803453 |
12 | 27750864b35 |
13 | 124cc820354 |
14 | 7c7937254d |
15 | 439ca454a8 |
hex | 25fc292759 |
163144345433 has 2 divisors, whose sum is σ = 163144345434. Its totient is φ = 163144345432.
The previous prime is 163144345381. The next prime is 163144345447. The reversal of 163144345433 is 334543441361.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123490393744 + 39653951689 = 351412^2 + 199133^2 .
It is an emirp because it is prime and its reverse (334543441361) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-163144345433 is a prime.
It is not a weakly prime, because it can be changed into another prime (163144345033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81572172716 + 81572172717.
It is an arithmetic number, because the mean of its divisors is an integer number (81572172717).
Almost surely, 2163144345433 is an apocalyptic number.
It is an amenable number.
163144345433 is a deficient number, since it is larger than the sum of its proper divisors (1).
163144345433 is an equidigital number, since it uses as much as digits as its factorization.
163144345433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 41.
Adding to 163144345433 its reverse (334543441361), we get a palindrome (497687786794).
The spelling of 163144345433 in words is "one hundred sixty-three billion, one hundred forty-four million, three hundred forty-five thousand, four hundred thirty-three".
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