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163325896010353 is a prime number
BaseRepresentation
bin100101001000101101000110…
…000000111010101001110001
3210102021210200111210222101201
4211020231012000322221301
5132401412413334312403
61335210514131131201
746254622650003046
oct4510550600725161
9712253614728351
10163325896010353
114804a13a4450aa
12163997a0143b01
1370197483b6b7b
142c490309291cd
1513d373493721d
hex948b4603aa71

163325896010353 has 2 divisors, whose sum is σ = 163325896010354. Its totient is φ = 163325896010352.

The previous prime is 163325896010327. The next prime is 163325896010383. The reversal of 163325896010353 is 353010698523361.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 160807050864784 + 2518845145569 = 12680972^2 + 1587087^2 .

It is a cyclic number.

It is not a de Polignac number, because 163325896010353 - 29 = 163325896009841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 163325896010294 and 163325896010303.

It is not a weakly prime, because it can be changed into another prime (163325896010383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81662948005176 + 81662948005177.

It is an arithmetic number, because the mean of its divisors is an integer number (81662948005177).

Almost surely, 2163325896010353 is an apocalyptic number.

It is an amenable number.

163325896010353 is a deficient number, since it is larger than the sum of its proper divisors (1).

163325896010353 is an equidigital number, since it uses as much as digits as its factorization.

163325896010353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10497600, while the sum is 55.

The spelling of 163325896010353 in words is "one hundred sixty-three trillion, three hundred twenty-five billion, eight hundred ninety-six million, ten thousand, three hundred fifty-three".