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163424013 = 354474671
BaseRepresentation
bin10011011110110…
…10011100001101
3102101111210121020
421233122130031
5313314032023
624114424353
74023036564
oct1157323415
9371453536
10163424013
1184280975
12468920b9
1327b1c0cc
14179c0bdb
15e531de3
hex9bda70d

163424013 has 4 divisors (see below), whose sum is σ = 217898688. Its totient is φ = 108949340.

The previous prime is 163424011. The next prime is 163424021. The reversal of 163424013 is 310424361.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 163424013 - 21 = 163424011 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (163424011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27237333 + ... + 27237338.

It is an arithmetic number, because the mean of its divisors is an integer number (54474672).

Almost surely, 2163424013 is an apocalyptic number.

It is an amenable number.

163424013 is a deficient number, since it is larger than the sum of its proper divisors (54474675).

163424013 is an equidigital number, since it uses as much as digits as its factorization.

163424013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54474674.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 163424013 is about 12783.7401804010. The cubic root of 163424013 is about 546.7288064319.

Adding to 163424013 its reverse (310424361), we get a palindrome (473848374).

The spelling of 163424013 in words is "one hundred sixty-three million, four hundred twenty-four thousand, thirteen".

Divisors: 1 3 54474671 163424013