Base | Representation |
---|---|
bin | 1001100001001000101… |
… | …1011001010000011001 |
3 | 120122001112221100010111 |
4 | 2120102023121100121 |
5 | 10134334003443134 |
6 | 203041150444321 |
7 | 14546010544102 |
oct | 2302213312031 |
9 | 518045840114 |
10 | 163513734169 |
11 | 633892706a5 |
12 | 278345036a1 |
13 | 1255b204676 |
14 | 7cb24493a9 |
15 | 43c01adc64 |
hex | 26122d9419 |
163513734169 has 2 divisors, whose sum is σ = 163513734170. Its totient is φ = 163513734168.
The previous prime is 163513734161. The next prime is 163513734173. The reversal of 163513734169 is 961437315361.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 162238172944 + 1275561225 = 402788^2 + 35715^2 .
It is a cyclic number.
It is not a de Polignac number, because 163513734169 - 23 = 163513734161 is a prime.
It is a super-2 number, since 2×1635137341692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (163513734161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81756867084 + 81756867085.
It is an arithmetic number, because the mean of its divisors is an integer number (81756867085).
Almost surely, 2163513734169 is an apocalyptic number.
It is an amenable number.
163513734169 is a deficient number, since it is larger than the sum of its proper divisors (1).
163513734169 is an equidigital number, since it uses as much as digits as its factorization.
163513734169 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1224720, while the sum is 49.
The spelling of 163513734169 in words is "one hundred sixty-three billion, five hundred thirteen million, seven hundred thirty-four thousand, one hundred sixty-nine".
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