Base | Representation |
---|---|
bin | 1110110111111101011000… |
… | …1100101011010010011010 |
3 | 2010220110220121022100011121 |
4 | 3231333112030223102122 |
5 | 4120423041220040010 |
6 | 54441100321115454 |
7 | 3305401413350101 |
oct | 355772614532232 |
9 | 63813817270147 |
10 | 16354534143130 |
11 | 5235a12186647 |
12 | 1a01750488b8a |
13 | 9182c2556161 |
14 | 4077c6a27038 |
15 | 1d56440143da |
hex | edfd632b49a |
16354534143130 has 8 divisors (see below), whose sum is σ = 29438161457652. Its totient is φ = 6541813657248.
The previous prime is 16354534143121. The next prime is 16354534143131. The reversal of 16354534143130 is 3134143545361.
It can be written as a sum of positive squares in 2 ways, for example, as 16327717133049 + 26817010081 = 4040757^2 + 163759^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (16354534143131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 817726707147 + ... + 817726707166.
Almost surely, 216354534143130 is an apocalyptic number.
16354534143130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
16354534143130 is a deficient number, since it is larger than the sum of its proper divisors (13083627314522).
16354534143130 is a wasteful number, since it uses less digits than its factorization.
16354534143130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1635453414320.
The product of its (nonzero) digits is 777600, while the sum is 43.
Adding to 16354534143130 its reverse (3134143545361), we get a palindrome (19488677688491).
The spelling of 16354534143130 in words is "sixteen trillion, three hundred fifty-four billion, five hundred thirty-four million, one hundred forty-three thousand, one hundred thirty".
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