Base | Representation |
---|---|
bin | 11110100001001101… |
… | …01010011100010011 |
3 | 1120021212200220102112 |
4 | 33100212222130103 |
5 | 232023440320011 |
6 | 11305500535535 |
7 | 1120012431134 |
oct | 172046523423 |
9 | 46255626375 |
10 | 16384698131 |
11 | 6a4880a23a |
12 | 32132515ab |
13 | 171169a969 |
14 | b160b1c8b |
15 | 65d68558b |
hex | 3d09aa713 |
16384698131 has 2 divisors, whose sum is σ = 16384698132. Its totient is φ = 16384698130.
The previous prime is 16384698101. The next prime is 16384698151. The reversal of 16384698131 is 13189648361.
16384698131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16384698131 is a prime.
It is a super-2 number, since 2×163846981312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 16384698131.
It is not a weakly prime, because it can be changed into another prime (16384698101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8192349065 + 8192349066.
It is an arithmetic number, because the mean of its divisors is an integer number (8192349066).
Almost surely, 216384698131 is an apocalyptic number.
16384698131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16384698131 is an equidigital number, since it uses as much as digits as its factorization.
16384698131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 746496, while the sum is 50.
The spelling of 16384698131 in words is "sixteen billion, three hundred eighty-four million, six hundred ninety-eight thousand, one hundred thirty-one".
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