Base | Representation |
---|---|
bin | 10111110110001100111… |
… | …111100000001111011011 |
3 | 12210122220011110200102201 |
4 | 113312030333200033123 |
5 | 203322123441402042 |
6 | 3252455212511031 |
7 | 226252463100532 |
oct | 27661477401733 |
9 | 5718804420381 |
10 | 1638747997147 |
11 | 581a97582228 |
12 | 22572547b477 |
13 | bb6c17a71c1 |
14 | 5945c8ad319 |
15 | 2c96320c1b7 |
hex | 17d8cfe03db |
1638747997147 has 2 divisors, whose sum is σ = 1638747997148. Its totient is φ = 1638747997146.
The previous prime is 1638747997123. The next prime is 1638747997163. The reversal of 1638747997147 is 7417997478361.
It is a strong prime.
It is an emirp because it is prime and its reverse (7417997478361) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1638747997147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1638747997147.
It is not a weakly prime, because it can be changed into another prime (1638747967147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 819373998573 + 819373998574.
It is an arithmetic number, because the mean of its divisors is an integer number (819373998574).
Almost surely, 21638747997147 is an apocalyptic number.
1638747997147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1638747997147 is an equidigital number, since it uses as much as digits as its factorization.
1638747997147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 448084224, while the sum is 73.
The spelling of 1638747997147 in words is "one trillion, six hundred thirty-eight billion, seven hundred forty-seven million, nine hundred ninety-seven thousand, one hundred forty-seven".
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