16393889191680 has 3456 divisors, whose sum is σ = 81204834686976. Its totient is φ = 2938739097600.

The previous prime is 16393889191661. The next prime is 16393889191699. The reversal of 16393889191680 is 8619198839361.

16393889191680 is a `hidden beast` number, since 1 + 6 + 393 + 8 + 8 + 91 + 91 + 68 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (16393889191661) and next prime (16393889191699).

It is a Harshad number since it is a multiple of its sum of digits (72).

It is a junction number, because it is equal to n+sod(n) for n = 16393889191599 and 16393889191608.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 47244637267 + ... + 47244637613.

It is an arithmetic number, because the mean of its divisors is an integer number (23496769296).

Almost surely, 2^{16393889191680} is an apocalyptic number.

16393889191680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 16393889191680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (40602417343488).

16393889191680 is an abundant number, since it is smaller than the sum of its proper divisors (64810945495296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

16393889191680 is a wasteful number, since it uses less digits than its factorization.

16393889191680 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 663 (or 646 counting only the distinct ones).

The product of its (nonzero) digits is 120932352, while the sum is 72.

The spelling of 16393889191680 in words is "sixteen trillion, three hundred ninety-three billion, eight hundred eighty-nine million, one hundred ninety-one thousand, six hundred eighty".