164096131 has 2 divisors, whose sum is σ = 164096132. Its totient is φ = 164096130.

The previous prime is 164096089. The next prime is 164096137. The reversal of 164096131 is 131690461.

164096131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 164096131 - 2¹³ = 164087939 is a prime.

It is a super-2 number, since 2×164096131² = 53855080418338322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 164096093 and 164096102.

It is not a weakly prime, because it can be changed into another prime (164096137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82048065 + 82048066.

It is an arithmetic number, because the mean of its divisors is an integer number (82048066).

Almost surely, 2^164096131 is an apocalyptic number.

164096131 is a deficient number, since it is larger than the sum of its proper divisors (1).

164096131 is an equidigital number, since it uses as much as digits as its factorization.

164096131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The square root of 164096131 is about 12810.0012099921. The cubic root of 164096131 is about 547.4772963070.

Subtracting from 164096131 its sum of digits (31), we obtain a square (164096100 = 12810²).

The spelling of 164096131 in words is "one hundred sixty-four million, ninety-six thousand, one hundred thirty-one".