Base | Representation |
---|---|
bin | 1001100011101111011… |
… | …0111000111110011010 |
3 | 120200212021201211110011 |
4 | 2120323312320332122 |
5 | 10142302012032023 |
6 | 203234410312134 |
7 | 14602231326163 |
oct | 2307366707632 |
9 | 520767654404 |
10 | 164213002138 |
11 | 63707a60009 |
12 | 279aa72864a |
13 | 126400487b3 |
14 | 7d3b27276a |
15 | 441178950d |
hex | 263bdb8f9a |
164213002138 has 4 divisors (see below), whose sum is σ = 246319503210. Its totient is φ = 82106501068.
The previous prime is 164213002117. The next prime is 164213002141. The reversal of 164213002138 is 831200312461.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 831200312461 = 2239 ⋅371237299.
It can be written as a sum of positive squares in only one way, i.e., 144526947889 + 19686054249 = 380167^2 + 140307^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41053250533 + ... + 41053250536.
Almost surely, 2164213002138 is an apocalyptic number.
164213002138 is a deficient number, since it is larger than the sum of its proper divisors (82106501072).
164213002138 is an equidigital number, since it uses as much as digits as its factorization.
164213002138 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82106501071.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 164213002138 its reverse (831200312461), we get a palindrome (995413314599).
The spelling of 164213002138 in words is "one hundred sixty-four billion, two hundred thirteen million, two thousand, one hundred thirty-eight".
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