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164213002138 = 282106501069
BaseRepresentation
bin1001100011101111011…
…0111000111110011010
3120200212021201211110011
42120323312320332122
510142302012032023
6203234410312134
714602231326163
oct2307366707632
9520767654404
10164213002138
1163707a60009
12279aa72864a
13126400487b3
147d3b27276a
15441178950d
hex263bdb8f9a

164213002138 has 4 divisors (see below), whose sum is σ = 246319503210. Its totient is φ = 82106501068.

The previous prime is 164213002117. The next prime is 164213002141. The reversal of 164213002138 is 831200312461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 831200312461 = 2239371237299.

It can be written as a sum of positive squares in only one way, i.e., 144526947889 + 19686054249 = 380167^2 + 140307^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41053250533 + ... + 41053250536.

Almost surely, 2164213002138 is an apocalyptic number.

164213002138 is a deficient number, since it is larger than the sum of its proper divisors (82106501072).

164213002138 is an equidigital number, since it uses as much as digits as its factorization.

164213002138 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82106501071.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 164213002138 its reverse (831200312461), we get a palindrome (995413314599).

The spelling of 164213002138 in words is "one hundred sixty-four billion, two hundred thirteen million, two thousand, one hundred thirty-eight".

Divisors: 1 2 82106501069 164213002138