Base | Representation |
---|---|
bin | 1001100011101111011… |
… | …0111000111110011101 |
3 | 120200212021201211110021 |
4 | 2120323312320332131 |
5 | 10142302012032031 |
6 | 203234410312141 |
7 | 14602231326166 |
oct | 2307366707635 |
9 | 520767654407 |
10 | 164213002141 |
11 | 63707a60011 |
12 | 279aa728651 |
13 | 126400487b6 |
14 | 7d3b27276d |
15 | 4411789511 |
hex | 263bdb8f9d |
164213002141 has 2 divisors, whose sum is σ = 164213002142. Its totient is φ = 164213002140.
The previous prime is 164213002117. The next prime is 164213002211. The reversal of 164213002141 is 141200312461.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 151484424100 + 12728578041 = 389210^2 + 112821^2 .
It is a cyclic number.
It is not a de Polignac number, because 164213002141 - 27 = 164213002013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (164213002111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82106501070 + 82106501071.
It is an arithmetic number, because the mean of its divisors is an integer number (82106501071).
Almost surely, 2164213002141 is an apocalyptic number.
It is an amenable number.
164213002141 is a deficient number, since it is larger than the sum of its proper divisors (1).
164213002141 is an equidigital number, since it uses as much as digits as its factorization.
164213002141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 164213002141 in words is "one hundred sixty-four billion, two hundred thirteen million, two thousand, one hundred forty-one".
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