Base | Representation |
---|---|
bin | 1110111100000110100111… |
… | …0100000100011010001011 |
3 | 2011011021200101020121200112 |
4 | 3233001221310010122023 |
5 | 4123104343412302011 |
6 | 54533513135424535 |
7 | 3313501623001463 |
oct | 357015164043213 |
9 | 64137611217615 |
10 | 16425730197131 |
11 | 52631275297a2 |
12 | 1a134bb98514b |
13 | 921c2a712b68 |
14 | 40b01c422ba3 |
15 | 1d740e63158b |
hex | ef069d0468b |
16425730197131 has 2 divisors, whose sum is σ = 16425730197132. Its totient is φ = 16425730197130.
The previous prime is 16425730197077. The next prime is 16425730197167. The reversal of 16425730197131 is 13179103752461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16425730197131 - 222 = 16425726002827 is a prime.
It is a super-2 number, since 2×164257301971312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 16425730197131.
It is not a weakly prime, because it can be changed into another prime (16425730197731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8212865098565 + 8212865098566.
It is an arithmetic number, because the mean of its divisors is an integer number (8212865098566).
Almost surely, 216425730197131 is an apocalyptic number.
16425730197131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16425730197131 is an equidigital number, since it uses as much as digits as its factorization.
16425730197131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 952560, while the sum is 50.
The spelling of 16425730197131 in words is "sixteen trillion, four hundred twenty-five billion, seven hundred thirty million, one hundred ninety-seven thousand, one hundred thirty-one".
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