Base | Representation |
---|---|
bin | 100101010110111011011111… |
… | …101101011000000100011001 |
3 | 210112202020212200112100001111 |
4 | 211112323133231120010121 |
5 | 133013421412112433132 |
6 | 1341235542115220321 |
7 | 46415350134100462 |
oct | 4526733755300431 |
9 | 715666780470044 |
10 | 164303432155417 |
11 | 48396770085325 |
12 | 16517132ba76a1 |
13 | 708a9936c2649 |
14 | 2c80485767d69 |
15 | 13edd98e96647 |
hex | 956edfb58119 |
164303432155417 has 2 divisors, whose sum is σ = 164303432155418. Its totient is φ = 164303432155416.
The previous prime is 164303432155363. The next prime is 164303432155427. The reversal of 164303432155417 is 714551234303461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120299897633161 + 44003534522256 = 10968131^2 + 6633516^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-164303432155417 is a prime.
It is not a weakly prime, because it can be changed into another prime (164303432155427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82151716077708 + 82151716077709.
It is an arithmetic number, because the mean of its divisors is an integer number (82151716077709).
Almost surely, 2164303432155417 is an apocalyptic number.
It is an amenable number.
164303432155417 is a deficient number, since it is larger than the sum of its proper divisors (1).
164303432155417 is an equidigital number, since it uses as much as digits as its factorization.
164303432155417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 49.
Adding to 164303432155417 its reverse (714551234303461), we get a palindrome (878854666458878).
The spelling of 164303432155417 in words is "one hundred sixty-four trillion, three hundred three billion, four hundred thirty-two million, one hundred fifty-five thousand, four hundred seventeen".
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