Base | Representation |
---|---|
bin | 1110111100100110000011… |
… | …0111111100111011110011 |
3 | 2011012002110120111212222001 |
4 | 3233021200313330323303 |
5 | 4123224140024422424 |
6 | 54541430433154431 |
7 | 3314221025314051 |
oct | 357114067747363 |
9 | 64162416455861 |
10 | 16434170154739 |
11 | 5266768683877 |
12 | 1a150763bba17 |
13 | 922974147a0c |
14 | 40b5bd2d31d1 |
15 | 1d7755584844 |
hex | ef260dfcef3 |
16434170154739 has 2 divisors, whose sum is σ = 16434170154740. Its totient is φ = 16434170154738.
The previous prime is 16434170154709. The next prime is 16434170154761. The reversal of 16434170154739 is 93745107143461.
It is a strong prime.
It is an emirp because it is prime and its reverse (93745107143461) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16434170154739 - 211 = 16434170152691 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16434170154739.
It is not a weakly prime, because it can be changed into another prime (16434170154709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8217085077369 + 8217085077370.
It is an arithmetic number, because the mean of its divisors is an integer number (8217085077370).
Almost surely, 216434170154739 is an apocalyptic number.
16434170154739 is a deficient number, since it is larger than the sum of its proper divisors (1).
16434170154739 is an equidigital number, since it uses as much as digits as its factorization.
16434170154739 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7620480, while the sum is 55.
The spelling of 16434170154739 in words is "sixteen trillion, four hundred thirty-four billion, one hundred seventy million, one hundred fifty-four thousand, seven hundred thirty-nine".
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