Search a number
-
+
164358000419953 is a prime number
BaseRepresentation
bin100101010111101110010100…
…001110110010010001110001
3210112221110201122100101112011
4211113232110032302101301
5133020320141101414303
61341321004550402521
746422321316511644
oct4527562416622161
9715843648311464
10164358000419953
114840792248410a
1216525821960441
137092b7ba1a782
142c82d80a93a5b
1514004de91116d
hex957b943b2471

164358000419953 has 2 divisors, whose sum is σ = 164358000419954. Its totient is φ = 164358000419952.

The previous prime is 164358000419891. The next prime is 164358000420013. The reversal of 164358000419953 is 359914000853461.

164358000419953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 147244828264704 + 17113172155249 = 12134448^2 + 4136807^2 .

It is a cyclic number.

It is not a de Polignac number, because 164358000419953 - 29 = 164358000419441 is a prime.

It is not a weakly prime, because it can be changed into another prime (164358000419453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82179000209976 + 82179000209977.

It is an arithmetic number, because the mean of its divisors is an integer number (82179000209977).

Almost surely, 2164358000419953 is an apocalyptic number.

It is an amenable number.

164358000419953 is a deficient number, since it is larger than the sum of its proper divisors (1).

164358000419953 is an equidigital number, since it uses as much as digits as its factorization.

164358000419953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13996800, while the sum is 58.

The spelling of 164358000419953 in words is "one hundred sixty-four trillion, three hundred fifty-eight billion, four hundred nineteen thousand, nine hundred fifty-three".