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1643993240081 is a prime number
BaseRepresentation
bin10111111011000101101…
…000100001001000010001
312211011102201022122001112
4113323011220201020101
5203413344232140311
63255123504343105
7226526453655143
oct27730550411021
95734381278045
101643993240081
11584239363945
1222674a014a95
13bc0493a114a
14597d936cc93
152cb6d95828b
hex17ec5a21211

1643993240081 has 2 divisors, whose sum is σ = 1643993240082. Its totient is φ = 1643993240080.

The previous prime is 1643993239997. The next prime is 1643993240167. The reversal of 1643993240081 is 1800423993461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1111582227856 + 532411012225 = 1054316^2 + 729665^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1643993240081 is a prime.

It is a super-2 number, since 2×16439932400812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1643993248081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 821996620040 + 821996620041.

It is an arithmetic number, because the mean of its divisors is an integer number (821996620041).

Almost surely, 21643993240081 is an apocalyptic number.

It is an amenable number.

1643993240081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1643993240081 is an equidigital number, since it uses as much as digits as its factorization.

1643993240081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1119744, while the sum is 50.

The spelling of 1643993240081 in words is "one trillion, six hundred forty-three billion, nine hundred ninety-three million, two hundred forty thousand, eighty-one".