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164404488673 is a prime number
BaseRepresentation
bin1001100100011101000…
…1010110100111100001
3120201100122001100121001
42121013101112213201
510143200022114143
6203305410432001
714610045045025
oct2310721264741
9521318040531
10164404488673
11637a6058747
1227a42892601
1312670911a39
147d5887a385
1544234b114d
hex26474569e1

164404488673 has 2 divisors, whose sum is σ = 164404488674. Its totient is φ = 164404488672.

The previous prime is 164404488667. The next prime is 164404488701. The reversal of 164404488673 is 376884404461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109682179489 + 54722309184 = 331183^2 + 233928^2 .

It is an emirp because it is prime and its reverse (376884404461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 164404488673 - 233 = 155814554081 is a prime.

It is a super-3 number, since 3×1644044886733 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (164404488373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82202244336 + 82202244337.

It is an arithmetic number, because the mean of its divisors is an integer number (82202244337).

Almost surely, 2164404488673 is an apocalyptic number.

It is an amenable number.

164404488673 is a deficient number, since it is larger than the sum of its proper divisors (1).

164404488673 is an equidigital number, since it uses as much as digits as its factorization.

164404488673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12386304, while the sum is 55.

The spelling of 164404488673 in words is "one hundred sixty-four billion, four hundred four million, four hundred eighty-eight thousand, six hundred seventy-three".