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16440450287713 is a prime number
BaseRepresentation
bin1110111100111101011100…
…1100110000100001100001
32011012200200020200200211121
43233033113030300201201
54123330020233201323
654544345534212241
73314532453465454
oct357172714604141
964180606620747
1016440450287713
1152693a0649711
121a16329654081
1392343527682a
1440ba173c349b
151d79c1aa4a5d
hexef3d7330861

16440450287713 has 2 divisors, whose sum is σ = 16440450287714. Its totient is φ = 16440450287712.

The previous prime is 16440450287699. The next prime is 16440450287717. The reversal of 16440450287713 is 31778205404461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9646540268544 + 6793910019169 = 3105888^2 + 2606513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16440450287713 is a prime.

It is a super-3 number, since 3×164404502877133 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (16440450287717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220225143856 + 8220225143857.

It is an arithmetic number, because the mean of its divisors is an integer number (8220225143857).

Almost surely, 216440450287713 is an apocalyptic number.

It is an amenable number.

16440450287713 is a deficient number, since it is larger than the sum of its proper divisors (1).

16440450287713 is an equidigital number, since it uses as much as digits as its factorization.

16440450287713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4515840, while the sum is 52.

The spelling of 16440450287713 in words is "sixteen trillion, four hundred forty billion, four hundred fifty million, two hundred eighty-seven thousand, seven hundred thirteen".