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16440950381497 is a prime number
BaseRepresentation
bin1110111100111111010100…
…0000011101101110111001
32011012201222002201002112121
43233033311000131232321
54123332031244201442
654544511321041241
73314551035303025
oct357176500355671
964181862632477
1016440950381497
11526962796a564
121a16449026221
139234b4a62505
1440ba639a1385
151d7a0093a967
hexef3f501dbb9

16440950381497 has 2 divisors, whose sum is σ = 16440950381498. Its totient is φ = 16440950381496.

The previous prime is 16440950381483. The next prime is 16440950381519. The reversal of 16440950381497 is 79418305904461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9266325636096 + 7174624745401 = 3044064^2 + 2678549^2 .

It is an emirp because it is prime and its reverse (79418305904461) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16440950381497 is a prime.

It is a super-3 number, since 3×164409503814973 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (16440950381477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220475190748 + 8220475190749.

It is an arithmetic number, because the mean of its divisors is an integer number (8220475190749).

Almost surely, 216440950381497 is an apocalyptic number.

It is an amenable number.

16440950381497 is a deficient number, since it is larger than the sum of its proper divisors (1).

16440950381497 is an equidigital number, since it uses as much as digits as its factorization.

16440950381497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26127360, while the sum is 61.

The spelling of 16440950381497 in words is "sixteen trillion, four hundred forty billion, nine hundred fifty million, three hundred eighty-one thousand, four hundred ninety-seven".