Base | Representation |
---|---|
bin | 1110111101000011010100… |
… | …0000011101001111101011 |
3 | 2011012211201221010201200022 |
4 | 3233100311000131033223 |
5 | 4123341231133340243 |
6 | 54545210035031055 |
7 | 3314616454034603 |
oct | 357206500351753 |
9 | 64184657121608 |
10 | 16442024121323 |
11 | 526a028a79149 |
12 | 1a166a873b48b |
13 | 92362634a518 |
14 | 40bb26425c03 |
15 | 1d7a64d35b68 |
hex | ef43501d3eb |
16442024121323 has 2 divisors, whose sum is σ = 16442024121324. Its totient is φ = 16442024121322.
The previous prime is 16442024121227. The next prime is 16442024121337. The reversal of 16442024121323 is 32312142024461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16442024121323 - 224 = 16442007344107 is a prime.
It is a super-3 number, since 3×164420241213233 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (16442024121223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221012060661 + 8221012060662.
It is an arithmetic number, because the mean of its divisors is an integer number (8221012060662).
Almost surely, 216442024121323 is an apocalyptic number.
16442024121323 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442024121323 is an equidigital number, since it uses as much as digits as its factorization.
16442024121323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 16442024121323 its reverse (32312142024461), we get a palindrome (48754166145784).
The spelling of 16442024121323 in words is "sixteen trillion, four hundred forty-two billion, twenty-four million, one hundred twenty-one thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •