Base | Representation |
---|---|
bin | 1110111101000100100001… |
… | …0000100100000111100001 |
3 | 2011012212120102220022001112 |
4 | 3233101020100210013201 |
5 | 4123342411330022011 |
6 | 54545302053513105 |
7 | 3314630455304246 |
oct | 357211020440741 |
9 | 64185512808045 |
10 | 16442347110881 |
11 | 526a184324a6a |
12 | 1a16778942795 |
13 | 9236782373c3 |
14 | 40bb572a15cd |
15 | 1d7a8338658b |
hex | ef4484241e1 |
16442347110881 has 2 divisors, whose sum is σ = 16442347110882. Its totient is φ = 16442347110880.
The previous prime is 16442347110851. The next prime is 16442347110929. The reversal of 16442347110881 is 18801174324461.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12776271020881 + 3666076090000 = 3574391^2 + 1914700^2 .
It is a cyclic number.
It is not a de Polignac number, because 16442347110881 - 214 = 16442347094497 is a prime.
It is a super-3 number, since 3×164423471108813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (16442347110851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221173555440 + 8221173555441.
It is an arithmetic number, because the mean of its divisors is an integer number (8221173555441).
Almost surely, 216442347110881 is an apocalyptic number.
It is an amenable number.
16442347110881 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442347110881 is an equidigital number, since it uses as much as digits as its factorization.
16442347110881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1032192, while the sum is 50.
The spelling of 16442347110881 in words is "sixteen trillion, four hundred forty-two billion, three hundred forty-seven million, one hundred ten thousand, eight hundred eighty-one".
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