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16442621503673 is a prime number
BaseRepresentation
bin1110111101000101100010…
…0111010010100010111001
32011012220021120012220012112
43233101120213102202321
54123343442101104143
654545345215022105
73314640326512241
oct357213047224271
964186246186175
1016442621503673
11526a3051a9372
121a1683480a935
139236c003a7c1
1440bb818cab21
151d7a9c4d7e18
hexef4589d28b9

16442621503673 has 2 divisors, whose sum is σ = 16442621503674. Its totient is φ = 16442621503672.

The previous prime is 16442621503667. The next prime is 16442621503729. The reversal of 16442621503673 is 37630512624461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14149311064249 + 2293310439424 = 3761557^2 + 1514368^2 .

It is a cyclic number.

It is not a de Polignac number, because 16442621503673 - 222 = 16442617309369 is a prime.

It is a super-3 number, since 3×164426215036733 (a number of 41 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (16442621503873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221310751836 + 8221310751837.

It is an arithmetic number, because the mean of its divisors is an integer number (8221310751837).

Almost surely, 216442621503673 is an apocalyptic number.

It is an amenable number.

16442621503673 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442621503673 is an equidigital number, since it uses as much as digits as its factorization.

16442621503673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 50.

The spelling of 16442621503673 in words is "sixteen trillion, four hundred forty-two billion, six hundred twenty-one million, five hundred three thousand, six hundred seventy-three".