Base | Representation |
---|---|
bin | 1110111101000101101100… |
… | …1001011010000011100011 |
3 | 2011012220101112012000121212 |
4 | 3233101123021122003203 |
5 | 4123344033441024023 |
6 | 54545353333540335 |
7 | 3314641353653336 |
oct | 357213311320343 |
9 | 64186345160555 |
10 | 16442664001763 |
11 | 526a32719585a |
12 | 1a16846aa46ab |
13 | 9236c8a9a3bc |
14 | 40bb873d061d |
15 | 1d7aa10cee78 |
hex | ef45b25a0e3 |
16442664001763 has 2 divisors, whose sum is σ = 16442664001764. Its totient is φ = 16442664001762.
The previous prime is 16442664001723. The next prime is 16442664001781. The reversal of 16442664001763 is 36710046624461.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16442664001763 is a prime.
It is a super-3 number, since 3×164426640017633 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (16442664001723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221332000881 + 8221332000882.
It is an arithmetic number, because the mean of its divisors is an integer number (8221332000882).
Almost surely, 216442664001763 is an apocalyptic number.
16442664001763 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442664001763 is an equidigital number, since it uses as much as digits as its factorization.
16442664001763 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3483648, while the sum is 50.
The spelling of 16442664001763 in words is "sixteen trillion, four hundred forty-two billion, six hundred sixty-four million, one thousand, seven hundred sixty-three".
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