Base | Representation |
---|---|
bin | 100101011000111011111011… |
… | …101111100111000010010011 |
3 | 210120020102211211012201002121 |
4 | 211120323323233213002103 |
5 | 133023201331403102111 |
6 | 1341423150454155111 |
7 | 46431331510601656 |
oct | 4530737357470223 |
9 | 716212754181077 |
10 | 164441341456531 |
11 | 4843a1aa303447 |
12 | 16539a00652a97 |
13 | 709a9a10a21b9 |
14 | 2c8700944b89d |
15 | 140276b38b871 |
hex | 958efbbe7093 |
164441341456531 has 2 divisors, whose sum is σ = 164441341456532. Its totient is φ = 164441341456530.
The previous prime is 164441341456477. The next prime is 164441341456597. The reversal of 164441341456531 is 135654143144461.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 164441341456531 - 225 = 164441307902099 is a prime.
It is a super-3 number, since 3×1644413414565313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (164441341156531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82220670728265 + 82220670728266.
It is an arithmetic number, because the mean of its divisors is an integer number (82220670728266).
Almost surely, 2164441341456531 is an apocalyptic number.
164441341456531 is a deficient number, since it is larger than the sum of its proper divisors (1).
164441341456531 is an equidigital number, since it uses as much as digits as its factorization.
164441341456531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8294400, while the sum is 52.
The spelling of 164441341456531 in words is "one hundred sixty-four trillion, four hundred forty-one billion, three hundred forty-one million, four hundred fifty-six thousand, five hundred thirty-one".
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