Base | Representation |
---|---|
bin | 1110111101100011101100… |
… | …0111111001111111111001 |
3 | 2011020200011201201001111102 |
4 | 3233120323013321333321 |
5 | 4124012031432000433 |
6 | 54553204354341145 |
7 | 3315345044352122 |
oct | 357307307717771 |
9 | 64220151631442 |
10 | 16450716671993 |
11 | 527278976811a |
12 | 1a1831388a7b5 |
13 | 9243b01c2126 |
14 | 40c30ca89049 |
15 | 1d7dc30314e8 |
hex | ef63b1f9ff9 |
16450716671993 has 2 divisors, whose sum is σ = 16450716671994. Its totient is φ = 16450716671992.
The previous prime is 16450716671953. The next prime is 16450716672043. The reversal of 16450716671993 is 39917661705461.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16327321141264 + 123395530729 = 4040708^2 + 351277^2 .
It is a cyclic number.
It is not a de Polignac number, because 16450716671993 - 212 = 16450716667897 is a prime.
It is not a weakly prime, because it can be changed into another prime (16450716671923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8225358335996 + 8225358335997.
It is an arithmetic number, because the mean of its divisors is an integer number (8225358335997).
Almost surely, 216450716671993 is an apocalyptic number.
It is an amenable number.
16450716671993 is a deficient number, since it is larger than the sum of its proper divisors (1).
16450716671993 is an equidigital number, since it uses as much as digits as its factorization.
16450716671993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51438240, while the sum is 65.
The spelling of 16450716671993 in words is "sixteen trillion, four hundred fifty billion, seven hundred sixteen million, six hundred seventy-one thousand, nine hundred ninety-three".
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