Base | Representation |
---|---|
bin | 11110101001100110… |
… | …10001010111000100 |
3 | 1120110210012022021111 |
4 | 33110303101113010 |
5 | 232200002042012 |
6 | 11320454054404 |
7 | 1121526100564 |
oct | 172463212704 |
9 | 46423168244 |
10 | 16455112132 |
11 | 6a84533328 |
12 | 323294a404 |
13 | 1723152a54 |
14 | b215a0da4 |
15 | 664943ba7 |
hex | 3d4cd15c4 |
16455112132 has 24 divisors (see below), whose sum is σ = 28906972920. Its totient is φ = 8196034560.
The previous prime is 16455112103. The next prime is 16455112151. The reversal of 16455112132 is 23121155461.
16455112132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 796594176 + 15658517956 = 28224^2 + 125134^2 .
It is a junction number, because it is equal to n+sod(n) for n = 16455112094 and 16455112103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1238388 + ... + 1251604.
It is an arithmetic number, because the mean of its divisors is an integer number (1204457205).
Almost surely, 216455112132 is an apocalyptic number.
It is an amenable number.
16455112132 is a deficient number, since it is larger than the sum of its proper divisors (12451860788).
16455112132 is a wasteful number, since it uses less digits than its factorization.
16455112132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14391 (or 14389 counting only the distinct ones).
The product of its digits is 7200, while the sum is 31.
Adding to 16455112132 its reverse (23121155461), we get a palindrome (39576267593).
The spelling of 16455112132 in words is "sixteen billion, four hundred fifty-five million, one hundred twelve thousand, one hundred thirty-two".
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