Base | Representation |
---|---|
bin | 1110111110101100001011… |
… | …0010110001000111001011 |
3 | 2011022112101122122202000012 |
4 | 3233223002302301013023 |
5 | 4124321403202414011 |
6 | 55010143132502135 |
7 | 3316634143025132 |
oct | 357530262610713 |
9 | 64275348582005 |
10 | 16470172701131 |
11 | 527aa63127846 |
12 | 1a2004361a94b |
13 | 926190c8a8c6 |
14 | 40d236a10919 |
15 | 1d866114aa8b |
hex | efac2cb11cb |
16470172701131 has 2 divisors, whose sum is σ = 16470172701132. Its totient is φ = 16470172701130.
The previous prime is 16470172701061. The next prime is 16470172701161. The reversal of 16470172701131 is 13110727107461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16470172701131 - 230 = 16469098959307 is a prime.
It is a super-2 number, since 2×164701727011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16470172701161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8235086350565 + 8235086350566.
It is an arithmetic number, because the mean of its divisors is an integer number (8235086350566).
Almost surely, 216470172701131 is an apocalyptic number.
16470172701131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16470172701131 is an equidigital number, since it uses as much as digits as its factorization.
16470172701131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49392, while the sum is 41.
Adding to 16470172701131 its reverse (13110727107461), we get a palindrome (29580899808592).
The spelling of 16470172701131 in words is "sixteen trillion, four hundred seventy billion, one hundred seventy-two million, seven hundred one thousand, one hundred thirty-one".
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