1648241113 has 2 divisors, whose sum is σ = 1648241114. Its totient is φ = 1648241112.

The previous prime is 1648241099. The next prime is 1648241131. The reversal of 1648241113 is 3111428461.

1648241113 = 28707² + 28708².

Together with next prime (1648241131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 824149264 + 824091849 = 28708^2 + 28707^2 .

It is an emirp because it is prime and its reverse (3111428461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1648241113 - 2¹⁷ = 1648110041 is a prime.

It is a super-3 number, since 3×1648241113³ (a number of 29 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1648241173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 824120556 + 824120557.

It is an arithmetic number, because the mean of its divisors is an integer number (824120557).

Almost surely, 2^1648241113 is an apocalyptic number.

1648241113 is the 28708-th centered square number.

It is an amenable number.

1648241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1648241113 is an equidigital number, since it uses as much as digits as its factorization.

1648241113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 31.

The square root of 1648241113 is about 40598.5358479835. The cubic root of 1648241113 is about 1181.2457190554.

Adding to 1648241113 its reverse (3111428461), we get a palindrome (4759669574).

The spelling of 1648241113 in words is "one billion, six hundred forty-eight million, two hundred forty-one thousand, one hundred thirteen".