Base | Representation |
---|---|
bin | 1111000000100000001110… |
… | …1000001111000000010101 |
3 | 2011102111210201122011220110 |
4 | 3300020003220033000111 |
5 | 4130324203224330401 |
6 | 55032334255353233 |
7 | 3322116136116555 |
oct | 360100350170025 |
9 | 64374721564813 |
10 | 16501325230101 |
11 | 52921999a3958 |
12 | 1a26098522819 |
13 | 9290b7065bba |
14 | 41095014d165 |
15 | 1d93860349d6 |
hex | f0203a0f015 |
16501325230101 has 4 divisors (see below), whose sum is σ = 22001766973472. Its totient is φ = 11000883486732.
The previous prime is 16501325230079. The next prime is 16501325230141. The reversal of 16501325230101 is 10103252310561.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 16501325230101 - 27 = 16501325229973 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16501325230141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2750220871681 + ... + 2750220871686.
It is an arithmetic number, because the mean of its divisors is an integer number (5500441743368).
Almost surely, 216501325230101 is an apocalyptic number.
It is an amenable number.
16501325230101 is a deficient number, since it is larger than the sum of its proper divisors (5500441743371).
16501325230101 is an equidigital number, since it uses as much as digits as its factorization.
16501325230101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5500441743370.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 16501325230101 its reverse (10103252310561), we get a palindrome (26604577540662).
The spelling of 16501325230101 in words is "sixteen trillion, five hundred one billion, three hundred twenty-five million, two hundred thirty thousand, one hundred one".
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