Base | Representation |
---|---|
bin | 100101100001010010101101… |
… | …001111111111000011011001 |
3 | 210122021022222102012012112012 |
4 | 211201102231033333003121 |
5 | 133112103321320123423 |
6 | 1342543032555355305 |
7 | 46520660110214621 |
oct | 4541225517770331 |
9 | 718238872165465 |
10 | 165015550161113 |
11 | 4864077a134a63 |
12 | 16611151a52b35 |
13 | 710cb905a0352 |
14 | 2ca6b1c207881 |
15 | 1412676d2e078 |
hex | 9614ad3ff0d9 |
165015550161113 has 2 divisors, whose sum is σ = 165015550161114. Its totient is φ = 165015550161112.
The previous prime is 165015550161041. The next prime is 165015550161149. The reversal of 165015550161113 is 311161055510561.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 139357151431369 + 25658398729744 = 11804963^2 + 5065412^2 .
It is a cyclic number.
It is not a de Polignac number, because 165015550161113 - 210 = 165015550160089 is a prime.
It is not a weakly prime, because it can be changed into another prime (165015550161173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82507775080556 + 82507775080557.
It is an arithmetic number, because the mean of its divisors is an integer number (82507775080557).
Almost surely, 2165015550161113 is an apocalyptic number.
It is an amenable number.
165015550161113 is a deficient number, since it is larger than the sum of its proper divisors (1).
165015550161113 is an equidigital number, since it uses as much as digits as its factorization.
165015550161113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67500, while the sum is 41.
The spelling of 165015550161113 in words is "one hundred sixty-five trillion, fifteen billion, five hundred fifty million, one hundred sixty-one thousand, one hundred thirteen".
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